Averages and Statistics
Overview
Mean, median, and range appear in roughly 15% of QR questions. The maths itself is straightforward - the UCAT makes it hard by asking you to work backwards (given the mean, find a missing value) or by burying numbers in frequency tables. The delta shortcut in this lesson is the single biggest time-saver for these problems.
Mean (Average)
The Three Rearrangements
The mean formula has three variables. Any question gives you two and asks for the third. Base formula: `Mean = Sum / n`.
| You know | You want | Formula |
|---|---|---|
| Sum and n | Mean | Mean = Sum / n |
| Mean and n | Sum | Sum = Mean × n |
| Mean and Sum | n | n = Sum / Mean |
The key rearrangement: `Sum = Mean × n`. This is the one most students forget and the one the UCAT tests most often.
Finding a Missing Value
Question type: "The mean of 5 numbers is 12. Four of them are 10, 14, 8, 15. What is the fifth?"
1.
Sum = Mean × n = 12 × 5 = 60
2. Sum of known values =10 + 14 + 8 + 15 = 47
3. Missing value =60 − 47 = 13
This works every time. But there's a faster way when the question asks about changes to the mean rather than a specific missing value.
The Change-in-Mean Shortcut (Delta Method)
This is the biggest time-saver in QR statistics. When a question asks what happens to the mean after adding, removing, or changing values, you don't need to calculate the old mean or the new mean separately.
The Formula
`Change in Mean = Change in Sum / n`
Worked Example
Question: A warehouse has 5 crates. 6 kg is added to each of 4 crates. By how much does the mean weight of the 5 crates change?
Delta method:
Change in sum =6 × 4 = 24 kg(added 6 to each of 4 crates)n = 5crates (total number stays the same)
Change in mean = `24 / 5 = 4.8 kg`
Done. No original values, no old mean, no new mean. One multiplication, one division.
Verification
Say the original crate weights are 10, 20, 30, 40, 50 kg. Mean = 150/5 = 30 kg.
After adding 6 kg to 4 crates: 16, 26, 36, 46, 50. Sum = 174. Mean = 174/5 = 34.8 kg.
Change = 34.8 - 30 = 4.8 kg. Matches.
When to Use It
| Use the delta shortcut when… | Don't use it when… |
|---|---|
| "By how much does the mean change?" | The question gives all values and asks for the mean directly |
| "A new item is added, what is the new mean?" | The question asks for a specific missing value (use `Sum = Mean × n`) |
| "One value increases / decreases by X" |
Adding or Removing an Item
When items are added or removed, you go through the sum. Mean × n = Sum is the bridge.
Adding an item: "Mean of 8 values is 25. A 9th value of 34 is added. New mean?"
Current sum =25 × 8 = 200. New sum =200 + 34 = 234. New mean =234 / 9 = 26.
Removing an item: "Mean of 10 values is 50. Value of 20 is removed. New mean?"
Current sum =50 × 10 = 500. New sum =500 − 20 = 480. New mean =480 / 9 = 53.3.
Worked Example: Frequency Table Mean
Question: The table below shows how many patients visited a clinic each day over 20 days. What's the mean number of daily visits?
| Daily visits | Number of days |
|---|---|
| 5 | 3 |
| 8 | 7 |
| 10 | 6 |
| 14 | 4 |
1. Total visits:
(5 × 3) + (8 × 7) + (10 × 6) + (14 × 4) = 15 + 56 + 60 + 56 = 187
2. Total days:3 + 7 + 6 + 4 = 20
3. Mean:187 / 20 = 9.35 visits per day
Calculator with memory:5 * 3 =(P) →8 * 7 =(P, memory 71) →10 * 6 =(P, memory 131) →14 * 4 = + C = 187→/ 20 = 9.35. Time: ~25 sec.
Trap: don't just average 5, 8, 10, 14 → that gives9.25. Wrong, because each value appears a different number of times. You need the weighted mean.
Median
What It Is
The median is the middle value when all values are arranged in order. Odd count: the single middle value. Even count: the average of the two middle values.
The Elimination Method
Don't sort the entire list. Cross off the highest and lowest in pairs until the middle remains.
Values:
23, 17, 31, 8, 42, 15, 29
Round 1: remove 8 (lowest) and 42 (highest) →23, 17, 31, 15, 29
Round 2: remove 15 and 31 →23, 17, 29
Round 3: remove 17 and 29 →23
Median = 23. No sorting required.
Even Number of Values
Values:
12, 45, 23, 67, 34, 8
Round 1: remove 8 and 67 →12, 45, 23, 34
Round 2: remove 12 and 45 →23, 34
Two values remain: Median = `(23 + 34) / 2 = 28.5`.
Which Position Is the Median?
For large datasets (like reading from a table with 100 entries), you need the position: `Position of median = (n + 1) / 2`.
| n | Position |
|---|---|
| 7 | 4 (the 4th value in sorted order) |
| 10 | 5.5 (average of 5th and 6th values) |
| 25 | 13 (the 13th value) |
Range
`Range = Highest value − Lowest value`.
That's it. But under time pressure it's easy to confuse this with mean or median. If a question says "range," you need the biggest number minus the smallest. Nothing else.
The Negative Number Trap
Problem: temperatures across 5 days:
17, 3, −3, 8, 12. What is the range?
Wrong:17 − 3 = 14(used 3 instead of −3 as lowest)
Right:17 − (−3) = 17 + 3 = 20
Subtracting a negative = adding. This trap appears in temperature, elevation, and profit/loss data.
Mode
The mode is the most frequently occurring value. Rare in QR but easy marks when it shows up.
Values:
3, 7, 2, 7, 5, 3, 7, 9, 3, 77appears 4 times - mode.3appears 3 times. Everything else appears once. Mode = 7.
For tables and charts, the mode is the value with the highest bar or most entries.
Combining Skills: Mean + Percentage
A common QR pattern combines both skills:
Problem: the mean salary of 8 employees is £32,000. If salaries increase by 5%, what is the new mean?
Slow:32,000 × 8 = 256,000, then× 1.05 = 268,800, then/ 8 = 33,600.
Fast:32,000 × 1.05 = 33,600. If every value increases by the same percentage, the mean increases by that same percentage. No need to find the sum at all.
Rule: A uniform percentage change applied to all values changes the mean by the same percentage. A uniform addition changes the mean by the same addition.
Common Traps
Trap 1: Confusing mean and median
Mean uses all values. Median uses only the middle. Read the question word carefully - they give different answers.
Trap 2: Weighted vs simple mean
"Average of 60 and 80" =
70(simple mean)
"Average of 60 (for 3 items) and 80 (for 7 items)" =(60×3 + 80×7) / 10 = 740/10 = 74(weighted mean)
If groups have different sizes, you need the weighted mean.
Trap 3: Forgetting to count all items
"Mean of 5 tests is 70. Sixth test is 88. New mean?"
nchanges from 5 to 6. New mean =(350 + 88) / 6 = 73, not(350 + 88) / 5 = 87.6.
Trap 4: Range with negative numbers
17 − (−3) = 20, not 14. Subtracting a negative = adding.
Summary
| Technique | When to Use | Formula / Method |
|---|---|---|
| Mean | "Average" / "mean" in question | Sum / n |
| Sum from mean | Finding missing values | Sum = Mean x n |
| Delta shortcut | "How much does mean change?" | Change in Mean = Change in Sum / n |
| Frequency table mean | Data given as value + frequency | Sum of (value x freq) / total freq |
| Median (elimination) | Finding middle value | Cross off highest+lowest in pairs |
| Median position | Large dataset | Position = (n+1) / 2 |
| Range | Highest - lowest | Watch for negatives: a - (-b) = a + b |
| Uniform % change | Same % applied to all values | New mean = Old mean x multiplier |
Next lesson: 3.5 Geometry - area, perimeter, and volume through decomposition, covering about 8% of QR questions.