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Probabilistic Reasoning
Decision Making6 min read

Probabilistic Reasoning

Section 01

Recognising This Question Type

These questions give you a scenario with numerical data - counters in a bag, success rates of machines, test results - and ask which option is most/least likely, or whether a probability claim is valid. They have 4 options and are worth 1 mark.

They make up ~4-5 questions (~11.1% of DM). Target time: 15-30 seconds for simple questions, 45-60 seconds for combined events.


Section 02

The Technique: The Comparison Table

Most PR questions ask you to compare options. The table makes that comparison mechanical.

Step 1: Identify the variables. What's being compared? What "considering only" factors does the question specify?

Step 2: Build a quick table. Options as rows, variables as columns. Fill in the numbers from the stimulus.

Step 3: Normalise the units. All values must be in the same format. Convert failure rates to success rates, fractions to percentages, or whatever gives you a like-for-like comparison.

Step 4: Find the winner. One option usually dominates. If two are close, calculate more precisely.

Step 5: Re-read the question. Did they ask for MOST likely or LEAST likely? Highest or lowest? This catches reversal errors - and they're more common than you'd think.


Section 03

The 5 Probability Principles You Need

You don't need advanced probability. These five principles cover every PR question in the UCAT.

#PrincipleFormula
1Basic probabilityP(event) = favourable outcomes / total outcomes
2Probabilities sum to 1P(red) + P(blue) + P(green) = 1
3Complement ruleP(at least one) = 1 − P(none)
4Independent events (AND)P(A and B) = P(A) × P(B) (only when events don't affect each other)
5Without replacementFirst draw 5/20, second draw 4/19 (total and favourable both drop by 1)

Section 04

The Framing Trap

This is the single most common trick in PR. The question presents numbers in deliberately mismatched formats so a quick glance gives the wrong answer.

Robot A: 78% success rate
Robot B: 4% failure rate

Quick glance: "78 > 4, so A is better." - wrong.
Convert to the same unit: Robot B's success rate = 100% − 4% = 96%. Robot B is far better.

Rule: Before comparing anything, convert all values to the same format. Success rates, percentages, fractions - pick one and convert everything.


Section 05

The Direction Trap

Students often confuse "probability of A given B" with "probability of B given A." These aren't the same thing.

"The probability that a person with the disease tests positive" is different from "the probability that a person who tests positive has the disease." When the question specifies a condition ("given that...", "considering only..."), check which group you're calculating within. The denominator changes depending on direction.


Section 06

Worked Example

Stimulus:

Some red counters and ten black counters are put in a bag and drawn out randomly one at a time. They aren't replaced after they're drawn out. The first three counters drawn out are red. Peter predicts the next counter will also be red.

Question: "The number of red counters originally in the bag must have been at least 14 if Peter is more likely to be correct than incorrect."

Options:

  • a) Yes, because with three reds drawn out the chance of the next counter being red is greater than one half.
  • b) Yes, because the reds were drawn more often so there are better odds red will be drawn out next.
  • c) Yes, because the reds were drawn more often so there are better odds black will be drawn out next.
  • d) No, there can only have been 13 red counters in the bag originally.
StepAction
Identify variablesRed counters remaining vs. black counters remaining after 3 draws
Set upOriginally: 14 red + 10 black = 24 total. After 3 red drawn: 11 red + 10 black = 21 remaining.
CalculateP(next is red) = 11/21. Is 11/21 > 1/2? Half of 21 is 10.5. 11 > 10.5. Yes.
Check with 13If originally 13 red: after 3 drawn, 10 red + 10 black = 20. P(red) = 10/20 = 1/2. Exactly even - not "more likely."
Re-read question"Must have been at least 14 if Peter is MORE likely to be correct." 14 works. 13 gives exactly 50/50, which isn't "more likely."
AnswerA - Yes, because with 14 originally (11 remaining), P(red) > 1/2

Time check: The key calculation is just "11 vs 10 remaining after 3 draws." Once you see that 14 - 3 = 11 red vs 10 black, the answer is immediate. ~20 seconds.


Section 07

Combined Events: The Multiplication Approach

Some questions ask about sequences of events:

"What is the probability of drawing two red counters in a row from a bag of 5 red and 3 blue?"

First draw: P(red) = 5/8
Second draw: P(red) = 4/7 (without replacement)
P(both red): 5/8 × 4/7 = 20/56 = 5/14

For "at least one" questions, use the complement:

"What is the probability of getting at least one head in two coin flips?"

P(no heads): 1/2 × 1/2 = 1/4
P(at least one head): 1 − 1/4 = 3/4


Section 08

The Pigeonhole Shortcut

Some questions ask: "What's the minimum number of draws to guarantee an outcome?" These aren't really probability questions - they're worst-case questions.

Bag: 5 red, 3 blue, 2 green. "Minimum draws to guarantee 2 green counters?"

Worst case: you draw all the red and all the blue first - that's 5 + 3 = 8 non-green. Then the next 2 draws must be green.
Answer: 8 + 2 = 10 draws

Formula: Minimum to guarantee X of type T = (total non-T items) + X


Section 09

Quick Decision Guide

When a PR question appears, spend 3 seconds classifying the subtype:

If the question is…Use this approach
Comparing rates / probabilities of optionsBuild a comparison table. Normalise units. Pick the winner.
"At least one" or "probability of none"Complement rule: P(at least one) = 1 − P(none)
Sequence of events (draw then draw)Multiply. Adjust denominator if without replacement.
"Minimum to guarantee"Pigeonhole: total non-target + required count
Rates given in mixed formatsStop. Normalise first. Then compare.

Section 10

Underlying Skills

PR questions test several skills from the DM taxonomy:

  • E1: Basic Probability Calculation - computing P = favourable / total for discrete outcomes
  • E2: Misleading Framing / Unit Mismatch - catching deliberately mismatched formats (success rate vs. failure rate, percentages vs. fractions)
  • E3: Combined / Joint Probability - multiplying probabilities for sequences, adjusting for without-replacement
  • E4: Worst-Case / Guarantee (Pigeonhole Principle) - minimum draws to guarantee an outcome
  • E5: Expected Value / Weighted Outcomes - multiplying probabilities by associated values

The comparison table handles E1 and E2 directly. Combined events (E3) need the multiplication rule. Pigeonhole questions (E4) need worst-case thinking, not probability at all.


Section 11

Common Mistakes

  1. Comparing mismatched units - 78% success vs. 4% failure looks like A > B until you convert. Always normalise first.
  2. Forgetting "without replacement" - The denominator changes after each draw. 5/20 then 4/19, not 4/20.
  3. Confusing "likely" with "guaranteed" - Probability questions ask what's most likely. Guarantee questions ask about worst-case certainty. Different logic entirely.
  4. Confusing conditional directions - P(A given B) isn't the same as P(B given A). Check which group is your denominator.
  5. Not re-reading the question - After calculating, check: did they ask for most likely or least likely? Highest or lowest? This reversal trap costs easy marks.

Section 12

Summary

ElementDetail
TechniqueComparison Table: list options as rows, variables as columns, normalise, compare
Time target15-30s simple, 45-60s combined events
Principle 1P = favourable / total
Principle 2Complement: P(at least one) = 1 - P(none)
Principle 3Independent events: P(A and B) = P(A) x P(B)
Principle 4Without replacement: denominator and numerator both decrease
Key trapMismatched units - always normalise before comparing

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