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Probabilistic Reasoning

Decision Making·Lesson 7 of 8·8 min read

Section 7.1

Recognising This Question Type

Probability questions give you a scenario with numerical data - counters in a bag, success rates of machines, prize-draw odds, transport reliability - and ask which option is most/least likely, or whether a probability claim is valid. Format: 4 options, 1 mark.

These make up ~4-5 questions (~11% of DM). Target time: 15-30 seconds for simple questions; 45-60 seconds for combined events.

Target time and triage

Probability is one of the best mark-per-minute trades in DM - the maths is GCSE-level, the patterns are repetitive, and only two rules cover the majority. Do these on the first pass.

The catch: probability questions are placed last in the DM exam order, so candidates who work front-to-back run out of time and miss them. The cure is triage: skip LP and complex Venn early to keep time for the last few probabilities.


Section 7.2

The two rules that do 80% of the work

Two ideas account for most UCAT probability questions:

Rule 1 - The complement rule

   P(at least one) = 1 − P(none)
   P(not A)         = 1 − P(A)

Whenever a question asks "probability of at least one X" - STOP. Don't add up "exactly one + exactly two + exactly three…". Compute P(no X) and subtract from 1. It's almost always faster.

Rule 2 - Translation / same-terms rule

Comparison questions deliberately phrase the two options in different units. One is given as a success rate; the other as a failure rate. One as a probability; the other as a frequency ("17 out of 20"). Before you compare, convert both to the same term.

  Crossfield: 0.15 probability of running LATE.
  Riverside:  on time 17 out of 20 journeys.

  Convert Riverside to P(late) = 3/20 = 0.15.
  Equal. (The trick is to spot this isn't 0.85 vs 0.15.)

These two rules drive both worked examples below.


Section 7.3

Worked example 1: Tanya's prize draws - the complement rule

Tanya enters two separate prize draws. The probability of winning the first is 0.3. The probability of winning the second is 0.4.

Question: Is Tanya more likely than not to win at least one prize?

Naive approach. Compute the three winning scenarios and add:

  • P(wins first only) = 0.3 × 0.6 = 0.18
  • P(wins second only) = 0.7 × 0.4 = 0.28
  • P(wins both) = 0.3 × 0.4 = 0.12
  • Sum = 0.58. "More likely than not" threshold is 0.5. Yes.

Three multiplications, one addition, one comparison. Easy to slip.

Complement approach.

  • P(wins at least one) = 1 − P(wins none)
  • P(wins none) = 0.7 × 0.6 = 0.42
  • P(wins at least one) = 1 − 0.42 = 0.58. More than half.

One multiplication, one subtraction, one comparison. Same answer, half the work.

Time check

~15 seconds with the complement. ~40 seconds without. The win scales with the number of trials - for 5 dice rolls, the naive method has dozens of cases; the complement still takes two lines.

*Reach for the complement whenever you see "at least one," "at least two," or "probability of getting any…"*** - and equally whenever you'd otherwise face a long sum of mutually exclusive cases.


Section 7.4

Worked example 2: Crossfield vs Riverside - the translation rule

Crossfield coaches and Riverside buses both operate the same route.
- Crossfield has a 0.15 probability of running late.
- Riverside services run on time on 17 out of every 20 journeys.
- Crossfield offers a refund on three quarters of its delayed services.
- Riverside has a 25% probability of not offering a refund when its service is delayed.

Question: Considering only punctuality and likelihood of receiving a refund when delayed, is Crossfield the better choice?

Build a comparison table. Two attributes, two options.

P(late)P(refund \delayed)
Crossfield0.15 (given)3/4 = 0.75 (given as a fraction)
Riversideon-time 17/20 → late 3/20 = 0.1525% will NOT refund → 0.75 will refund

Same terms now. P(late) is identical. P(refund when delayed) is identical. Crossfield is not better - they're equivalent. Answer: No.

Time check

~45 seconds - most of it spent building the table and translating. The mistake to avoid: leaving Riverside as "on time 17/20" and Crossfield as "late 0.15" and concluding they're different because the numbers look different.

The translation step is the whole technique. Once both numbers are in the same units, the answer falls out.


Section 7.5

The five principles you actually need

#PrincipleForm
1Basic probabilityP = favourable / total
2Probabilities sum to 1P(A) + P(not A) = 1
3ComplementP(at least one) = 1 − P(none)
4Independent events (AND)P(A and B) = P(A) × P(B)
5Without replacementDenominator AND favourable count both drop by 1 each draw

You will not need conditional probability formulas, Bayes' theorem, or expected value tables. This is the entire toolkit.


Section 7.6

The framing trap

The single most common PR trick: numbers given in deliberately mismatched formats.

Stimulus saysQuick glance getsConvert to
"78% success rate" vs "4% failure rate"A > B (78 > 4)A = 78%, B = 96% → B wins
"0.15 probability of running late" vs "on time 17/20"They look differentBoth = P(late) = 0.15 → equal
"twice as likely as" vs raw probabilitiesConfusionConvert "twice" into a probability

Rule: before comparing anything, convert all values to the same unit.


Section 7.7

The direction trap

P(A given B)P(B given A). The denominator changes depending on which group you're conditioning on.

"The probability that a person with the disease tests positive" (denominator = people with the disease)



"The probability that a person who tests positive has the disease" (denominator = people who tested positive)

When you see "given that", "considering only", "out of all the…" - check which group sits in the denominator before computing.


Section 7.8

Combined events

Sequences of events use multiplication, with the without-replacement adjustment if relevant.

Bag of 5 red and 3 blue. Two draws without replacement. P(two reds)?

First draw: P(red) = 5/8.
Second draw, given first was red: P(red) = 4/7.
P(both red) = 5/8 × 4/7 = 20/56 = 5/14.

For "at least one" questions, always use the complement instead of summing.


Section 7.9

The pigeonhole shortcut

Some questions ask "minimum number of draws to guarantee X." These aren't probability questions at all - they're worst-case questions.

Bag: 5 red, 3 blue, 2 green. "Minimum draws to guarantee 2 green?"

Worst case: you draw every red and every blue first → 5 + 3 = 8 non-green.
The next 2 draws must be green.
Answer: 8 + 2 = 10 draws.

Formula: Minimum to guarantee X of type T = (all non-T items) + X.


Section 7.10

Quick decision guide

PR question appears.
   |
   ├── Comparing two options with different units?
   │     → Translation rule. Convert to same terms. Build a table.
   │
   ├── "At least one" / "at least two" / "any"?
   │     → Complement. P(at least one) = 1 − P(none).
   │
   ├── Sequence of independent events (draw then draw)?
   │     → Multiply. Adjust denominator if without replacement.
   │
   ├── "Minimum to guarantee" / "in the worst case"?
   │     → Pigeonhole. Sum non-target items, add required count.
   │
   └── "Given that…" / "out of those who…"?
       → Check which group is in the denominator. Direction matters.

Section 7.11

Common Mistakes

  1. Comparing mismatched units. Always translate first.
  2. Summing cases instead of using the complement. The moment you see "at least one," reach for 1 − P(none).
  3. Forgetting without-replacement. After each draw, both numerator and denominator drop by 1.
  4. Confusing "likely" with "guaranteed". Probability questions are about likelihood; pigeonhole questions are about worst-case certainty. Different logic.
  5. Mixing up conditional direction. P(positive | disease) ≠ P(disease | positive).
  6. Not re-reading the question. "Most likely" vs "least likely," "more than half" vs "less than half." Reversal traps cost easy marks.

Section 7.12

Summary

ElementDetail
Format4 options, 1 mark
Two key rulesComplement (P(at least 1) = 1 − P(none)); Translation (convert to same units)
Five principlesBasic P, sum to 1, complement, multiplication (AND), without-replacement
Time target15-30s simple; 45-60s combined events
Default strategyAttempt early - high yield per minute
Key trapFraming - values given in mismatched units
Pigeonhole formula(Non-target count) + required count

Section 7.13

Underlying Skills

Probability questions test five skills:

  • E1: Basic Probability Calculation - computing P = favourable / total for discrete outcomes.
  • E2: Misleading Framing / Unit Mismatch - catching deliberately mismatched formats (success vs failure, fraction vs probability).
  • E3: Combined / Joint Probability - multiplying for sequences, adjusting for without-replacement.
  • E4: Worst-Case / Guarantee (Pigeonhole Principle) - minimum draws to guarantee an outcome.
  • E5: Expected Value / Weighted Outcomes - multiplying probabilities by their associated values.

The two key rules (complement, translation) cover E1, E2, and most of E3. E4 is pigeonhole. E5 is rare and follows from E1 + multiplication.